h = -16t2+v0t+h0
The formula translates to this when you add in the variables for height and velocity. 192 ft/sec is the velocity, 32 feet is the height.
h= -16t2+192t+32
I plugged the formula into my graphing calculator and then I went to the table to find the maximum height that it goes on the y-axis. In this case, the maxium height was 608 feet.
Then, to find how long the cannonball is in the air, you plug the a, b, and c values into the quadratic formula, which is this:
-b ±√(b2-4ac)/2a
With the variables plugged in, the formula now looks something like this.
-192±√((192)2-4(-16)(32))/2(-16)
When you plug this into your calculator, the answer comes out to be about 12 seconds in the air.
excellent job explaining the process :D
ReplyDeleteYay you did really welll on this math section
ReplyDelete*well (my bad)
ReplyDeleteThis is really pretty and well set up! I love it!
ReplyDeletevery descriptive! good job darling.
ReplyDelete